how do u find the 'n' term in a quadratic pattern please help!

RyanS
Tn= an^2 + bn + c
a = double second difference (so half this second difference and put in instead of a)
for n you sub in the term no. i.e. term 1, 2, 3... and let it be equal to that term
then simultaneous equations
Example:
Find term n (general term) of:
1, 5, 10, 16
Okay so second difference is +1
Thus, 2a = 1
a = 0.5
=> 0.5n^2 + bn + c
First term is 1
=> 0.5(1)^2 + b(1) + c = 1
0.5 + b + c =1
b + c = 0.5
Second Term is 5
=> 0.5(2)^2 + b(2) + c = 5
2 + 2b + 2c = 1
2b + 2c = 1
Now Simultaneous equations.. Note that any term can be used, but 1st and 2nd Term is generally much easier :)

hamzamughees
https://www.youtube.com/watch?v=dFTRZONntq8

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