How do you do the above!

sarah_mccutcheon
To do pythagoras you must allow the square of the hypotenuse equal the sum of the squares of the other two sides of the triangle.
EXAMPLE: you have a triangle with a hypotenuse labeled x and the two other sides are labeled 4 and 3
so to find the value of x we say x to be squared = 4 to be squared + 3 to be squared
this means x to be squared is =16+9
x squared = 25
to find x on its own you get the square root in this case its the square root of 25 which is 5.
To do simultaneous equations you must make sure that either the x or y value are the same and have different signs(+ or ) if they do not you multiply one of the lines by a value that will let either the x or y value be equal and make sure the signs are different before you cross away the x or y value then solve for either either x or y and when you have, sub the value you have found back in to one of the original equations and solve for the other value you have not already found

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