How do you do the above!
To do pythagoras you must allow the square of the hypotenuse equal the sum of the squares of the other two sides of the triangle.
EXAMPLE: you have a triangle with a hypotenuse labeled x and the two other sides are labeled 4 and 3
so to find the value of x we say x to be squared = 4 to be squared + 3 to be squared
this means x to be squared is =16+9
x squared = 25
to find x on its own you get the square root in this case its the square root of 25 which is 5.
To do simultaneous equations you must make sure that either the x or y value are the same and have different signs(+ or -) if they do not you multiply one of the lines by a value that will let either the x or y value be equal and make sure the signs are different before you cross away the x or y value then solve for either either x or y and when you have, sub the value you have found back in to one of the original equations and solve for the other value you have not already found