Arthur wants to fence three sides of his rectangular garden. The fourth side of the garden faces into the back of his house. He has 80 metres of fencing. Let x represent the width of his garden and let y represent the length of his garden.
i) show that y = 802x
ii) write an expression for the area of the garden in terms of x
iii) if the garden has an area of 487.5m^2 find two possible values for the width and length of the garden
How would I answer these I'm so stuck

roro123
y is 802x as the 3 sides add up to 80. To get the length (y) you take away the width (x) times 2 as this are has 1 length and 2 widths.

roro123
(ii) area = x times y (width times length). width=x and length= 802x. therefor area is (x)(802x) which is 80x2x^2.

roro123
(iii) 80x2x^2=487.5 = 2x^2+80x487.5=0. Solve this using the b formula.

roro123
I think they are all right, sorry if they are wrong. I didn't write out how to finish (iii) as i can't type it!!

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