All Leaving Cert Applied Maths posts
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    2015 - Question 1 part a) Stormcrow

    Just wondering about the accepted answering of this question:

    "A particle starts from rest, constant acceleration

    It travels 39m in the 7th second. What distance does it travel in the 10th second"

    The marking scheme allows s7 - s6 to equal 39

    => s7 - s6 = 1/2(a)(49) -1/2(a)(36)

    and solves for a = 6

    I get the velocity of the particle AFTER 6 seconds in terms of a and sub into s = ut + 1/2at^2.

    Both solutions work, would both be accepted???

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      hamzamughees

      Yes both would be accepted, they are looking for working and answers, not specific ways.

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      Me

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