Can someone please tell me where the solutions are getting 1.14g of anhydrous sodium carbonate? I can't figure it out!
You can check tha marking scheme ...
(ii) 0.0108 x 106g (Mr of Na2CO3) = 1.1448g/L
Mass of water of crystallisation
sample of crystals were 2.50g and you have found the grams per litre above...
= 2.50 - 1.1448 = 1.3552g
% water of crystallisation = 1.3552/2.50 x 100 = 54.21%
x = moles of H2O/moles of Na2CO3
= 0.0752/0.0108 = 6.96
x = 7