does any budy know how to do he 2013 kc question 9 part c i need help on it

lilymelvin
Fe CNS Fe(CNS)
I 1x10^3 1x10^3 0
C (1.1x10^4) (1.1x10^4) +(1.1x10^4)
E 8.9x10^4 8.9x10^4 1.1x10^4
1.1x10*4/(8.9x10*4)^2 = 138.87

liamcro97
kc= concentration of products divided by the reactants therefore it's Fe(CNS) divided by (Fe x CNS)
So take your equation and leave three lines under it.
Fe + CNS > Fe(CNS)
Initial: 1x10 to power of 3 1x10 to power of 3 0 (as isnt present at beginning)
Change minus 1.1x10 to power 4 for both these add 1.1x10 to power 4 therefore subtract on other side
@equilibrium 0.00089 0.00089 We are told 1.1x10 to power of 4
So products divided by reactants= 1.1x10 to power of 4 over (0.00089) squared gives you 138.87 which is Kc
Hope that helps xo

Me
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