Could someone please solve this log equation please? Much appreciated!
log5(x+1) + log4(x+1) = 3

Rdonegan
if you insert x=8.34 into your calculator for this problem it will give you a result of 2.999963804

Rdonegan
if the bases are not given. Then normally they can both be taken to the base 10, common log.
log 5(x+1)* 4(x+1) = 3
20 (x+1)sq = 10 cubed
x = 50sqroot  1
x equal very close to 6

flashgut
U spelled LOGARITHM WRONG..... Hope that helps

Me
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