This Question is on CALCULUS:
Find the point on the curve f(x) = x2 (X Squared)  6x + 11 where the tangent is parallel to the xaxis?
Thank you :)

lalaloopsy15
is it h.l or o.l

Dazzla16
Here's the solution:
The tangent of the curve parallel to the xaxis will have a slope of 0.
Then we find the derivative of f(x) = x^2  6x + 11 to find the slope of any tangent.
dy/dx = 2x  6
If slope = 0,
2x  6 = 0
2x = 6
x = 3
Then we find the corresponding yvalue for x = 3
y = (3)^2  6(3) + 11 = 9  18 + 11 = 2
Therefore the point is (3,2)

jamielovesmusic123
Thak you Dazzla16 :)

Me
Share files from your computer